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2 years ago

What is the percent by mass of oxygen in carbon dioxide (CO2)?

Chemistry

2 answers:

krok68 [10]2 years ago

8 0

Answer:

I think that it will be

Explanation:

72.71%

vesna_86 [32]2 years ago

5 0

Answer:

72.71%

Explanation:

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Elements A,B,C and D have atomic numbers 11,18,1 and 17 respectively. Give the chemical formulae of the compound formed between:

SpyIntel [72]

Answer: a ) NaCl

b) No compound.

Explanation:

Atomic number of A is 11 , thus it is sodium. It has electronic configuration of 2,8,1 and thus has 1 valence electron and can form $Na^+$ .

Atomic number of B is 18 , thus it is argon. It has electronic configuration of 2,8,8 and thus it is an inert gas.

Atomic number of C is 1 , thus it is hydrogen. It has electronic configuration of 1. It can only share electrons.

Atomic number of D is 17 , thus it is chlorine. It has electronic configuration of 2,8,7 and thus has 7 valence electron and can form $Cl^-$ .

a) A and D :

Here Sodium is having an oxidation state of +1 called as $Na^+$ cation and anion is $Cl^-$ . Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $NaCl$

b) B and C

As B is an inert gas , it wont combine with C.

4 0

2 years ago

If the reactants have a potential energy of 10.2 kJ/mol and the products have a potential energy of 15.7 kJ/mol, what is ΔH?

Alex Ar [27]

Answer:

your answer

Explanation:

Download pdf

6 0

2 years ago

Someone help me please ??

jolli1 [7]

Okay your answer is 1 I think

4 0

3 years ago

Convert 4.92 L of hydrogen at STP to moles.

Lorico [155]

${\huge{\fcolorbox{yellow}{red}{\orange{\boxed{\boxed{\boxed{\boxed{\underbrace{\overbrace{\mathfrak{\pink{\fcolorbox{green}{blue}{Answer}}}}}}}}}}}}}$

$\sf C) \: 0.220 \: mol \: H_2$

Explanation:

1 mol = 22.4 litres

4.92 = how many moles?

$\sf \implies \frac{4.92}{22.4} \\ \\ \sf \implies 0.2196 \\ \\ \sf \implies 0.220 \: mol \: H_2$

5 0

1 year ago

Read 2 more answers

Considering the following precipitation reaction: Pb(NO3)2(aq) + 2KI(aq) → PbI2(s) + 2KNO3(aq),

patriot [66]

Answer: The ions which are not spectator ions are $Pb^{2+}$ and $I^-$

Explanation:

Spectator ions are defined as the ions which does not get involved in a chemical equation or they are ions which are found on both the sides of the chemical reaction present in ionic form.

The given chemical equation is:

$Pb^{2+}(aq)+NO_3^-(aq)+2K^+(aq)+2I^-(aq)\rightarrow PbI_2(s)+2K^+(aq)+2NO_3^-(aq)$

The ions which are present on both the sides of the equation are $K^+$ and $NO_3^-$ and are spectator ions.

Thus the net ionic equation is:

$Pb^{2+}(aq)+2I^-(aq)\rightarrow PbI_2(s)$

Hence, the correct answer is $Pb^{2+}$ and $I^-$

5 0

2 years ago

Read 2 more answers