Answer:
Argon {Ar}
Explanation:
The noble gas used for a condensed electron configuration is the one before the element which you are configuring.
In this case, the element (Mn) is manganese
The noble gas that is before this element is Argon which is the row above it
so your configuration would be {Ar} 3d^5 4s^2
The number of C atoms in 0.524 moles of C is 3.15 atoms.
The number of molecules in 9.87 moles is 59.43 molecules.
The moles of Fe in 1.40 x atoms of Fe is 0.23 x
The moles of in 2.30x molecules of is 3.81.
<h3>What are moles?</h3>
A mole is defined as 6.02214076 × of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.
A. The number of C atoms in 0.524 mole of C:
6.02214076 × x 0.524 mole
3.155601758 atoms =3.155 atoms
B. The number of molecules in 9.87 moles of :
6.02214076 × x 9.87
59.4385293 molecules= 59.43 molecules
C. The moles of Fe in 1.40 x atoms of Fe:
1.40 x ÷ 6.02214076 ×
0.2324754694 x moles.
0.23 x moles.
D. The moles of in 2.30x molecules of :
2.30x ÷ 6.02214076 ×
3.819239854 moles=3.81 moles
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The formal charge of H = +1, because F in compounds can have only -1.
Answer:3.6 I think sorry if wrong
Explanation:
90 divided by 25
Answer:The volume of the remaining gas that is ammonia is 23.85 L.
Explanation:
Moles of
Moles of HCl of gas =
According to reaction 1 mole of HCl reacts with 1 mol of then 2.06 moles of HCl will react with = 2.06 moles of
Moles left of ammonia left = 4.43 - 2.06 = 2.36 moles
Volume of the gas will be given by Ideal gas equation: PV=nRT
Pressure = 752 mmHg = 752 × 0.0031 atm = 2.33 atm
R = 0.08026 L atm/K mol
V = ? , n = number of moles of ammonia
Temperature = 14 °C = 14 + 273 K = 287 K(0°C = 273K)
The volume of the remaining gas that is ammonia is 23.85 L.