Undefined slope is rise/0
run is equal to 0
that means it doesn't go left or right
means it is vertcal
means it is x=somethig
(x,y)
(-6,4)
x=-6 is the equation
oh, forgot about standard form
standard form is
ax+by=c
so
x+0y=-6 would be the equation in standard form
0 solutions
move the x to one side, and the numbers to the other.
12x (-12x) + 32 (-32)= 12 (-12x) - 7 (-32)
12x - 12x = -7 - 32
0 = -39
0 ≠ -39
∴ you have 0 solutions
hope this helps
You can just use the app SnapCalc it answers anything for free
Answer:
2 roots in every case, not all are real.
Step-by-step explanation:
All of these equations are quadratic equations (degree 2). Every quadratic has two roots. They may be identical (looks like 1 root), and they may be complex (zero real roots), but there are always 2 of them.
a) the y-value of the vertex is negative and the parabola opens downward (leading coefficient -5), so there are no real zeros and both roots are complex.
b) each binomial factor contributes a root. Both roots are real.
c) the discriminant is positive, (3²-4·2·1=1), so both roots are real.
I believe that you could factor (x+1) out of the polynomial
