X=y-4 and 2x+4y=10 help me
1 answer:
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Question says to draw a polygon with the given conditions in a coordinate plane. It is talking about Rectangle with perimeter of 20 units.
So we can use formula of perimeter of rectangel to find it's possible dimensions.
We knwo that perimeter of the rectangle is given by 2(L+W)
where L is lenght and W is width.
Given perimeter is 20 so we get:
2(L+W)=20
L+W=10
L=10-W
So basically we can use any number for W which can be from 0 to 10 as side length can't be negative.
Let W=4
Then L=10-W=10-4=6
Hence we just have to draw a rectangle having length 6 and width 4.
So the final answer will be picture in the attached graph.
Answer:
66cm²
Step-by-step explanation:
Okay so lets start by breaking this down and writing a smiple equation to find the area.
We know that the N's are the same size. To make it easier we can turn them to a square/rectangle. I think it would be easist to move the bottem N's to the top. (look at the pic attached to see what i mean)
Lets start by finding the area of the top rectangle. We need to divide 8 by 2 to find the height.
a = b * h
a = 12 * 4 = 48(area of top rectangle)
a(of m) = 4.5 * 4 = 18
area of the whole thing:
a = 48 + 18 = 66
