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2 years ago

12

Whats 2+4323693743564868543789

1 answer:

insens350 [35]2 years ago

6 0

The answer of 2+4323693743564868543789=4323693743564868543791

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<img src="https://tex.z-dn.net/?f=%5Cint%5Climits%5E4_3%7Bx%5E%7B2%7D-x%20%7D%20%5C%2C%20dx" id="TexFormula1" title="\int\limits

melisa1 [442]

Answer:

$\frac{53}{6}$

Step-by-step explanation:

$\int\limits^4_3 {x^2-x} \, dx$

= [ $\frac{x^3}{3}$ - $\frac{x^2}{2}$ ] ← evaluate for upper limit - lower limit

= ( $\frac{64}{3}$ - $\frac{16}{2}$ ) - ( $\frac{27}{3}$ - $\frac{9}{2}$ )

= $\frac{64}{3}$ - 8 - 9 + $\frac{9}{2}$

= $\frac{155}{6}$ - 17

= $\frac{53}{6}$

5 0

2 years ago

Please help me! I will give it 5 stars and I will heart the answer!

andrew11 [14]

Answer:

Haha there is no question

Step-by-step explanation:

4 0

2 years ago

Seven more than a number is more

GalinKa [24]

Answer:

x+7>

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

What is the value of x?

Airida [17]

x=84

Add up all the sides and then subtract that number by the original amount of degrees. 540

6 0

3 years ago

Read 2 more answers

Consider f and c below. f(x, y, z) = yzexzi + exzj + xyexzk,

Jet001 [13]

Answer:

$f(x,y,z)=ye^{xz}+C$

Step-by-step explanation:

We can write the given expression as :

$\vec f(x,y,z)=yze^{xz}\,\vec\imath+e^{xz}\,\vec\jmath+xye^{xz}\,\vec k$

As given, f = ∇f.

∇f = $\dfrac{\partial f}{\partial x}i$ + $\dfrac{\partial f}{\partial y}j$ + $\dfrac{\partial f}{\partial z}k$

We can write the partial derivative with respect to x, y and z.

$\dfrac{\partial f}{\partial x}=yze^{xz}$ ___(Equation 1)

$\dfrac{\partial f}{\partial y}=e^{xz}$ ______(Equation 2)

$\dfrac{\partial f}{\partial z}=xye^{xz}$ ______(Equation 3)

Take equation 2 and integrate with respect to y,

$\dfrac{\partial f}{\partial y}=e^{xz}$

$f(x,y,z)=ye^{xz}+a(x,z)$ ----------Equation 4

Derivate both sides w.r.t x , we get :

$\frac{d}{dx}(yze^{xz})=yze^{xz}+\dfrac{\partial a}{\partial x}$

or

$\dfrac{\partial a}{\partial x}=0$

integrate

a(x,z)=b(z)

put in equation 4 ,

we get :

$f(x,y,z)=ye^{xz}+b(z)$

take derivative wrt z

$\frac{d}{dz} (ye^{xz}+b(z))\impliesxye^{xz}=xye^{xz}+\frac{db}{dz}$

we can take here:

$\frac{db}{dz} = 0$

integrate:

$\int\ {\frac{db}{dz} } \, =\int0$

b(z) = C

The function can be written as :

from equation 4 :

$f(x,y,z)=ye^{xz}+C$

Where C is a constant.

4 0

2 years ago