The ratio of boys to girls at the beach cleanup was 7:8. If there were 42 boys, how many girls were there?
1 answer:
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Given:
μ = 500 days, the population mean
σ = 60 days, the population standard deviation
Therefore
μ + σ = 560
μ - σ = 440
μ + 2σ = 620
μ - 2σ = 380
μ + 3σ = 680
μ - 3σ = 320
The figure shown below illustrates the normal distribution
About 68% of the total area lies in x = (μ-σ, μ+σ)
About 95% of the total area lies in x = (μ-2σ, μ+2σ)
About 99.7% of the total area lies in x = (μ-3σ, μ+3σ).
μ = 500 days, the population mean
σ = 60 days, the population standard deviation
Therefore
μ + σ = 560
μ - σ = 440
μ + 2σ = 620
μ - 2σ = 380
μ + 3σ = 680
μ - 3σ = 320
The figure shown below illustrates the normal distribution
About 68% of the total area lies in x = (μ-σ, μ+σ)
About 95% of the total area lies in x = (μ-2σ, μ+2σ)
About 99.7% of the total area lies in x = (μ-3σ, μ+3σ).
Answer:
hello your question is incomplete attached below is the complete question
answer :
H0 : <em> u </em>= 21.62 ( Null hypothesis )
H1 : <em> u</em> = 21.62 ( alternative hypothesis )
Step-by-step explanation:
Formulating hypothesis that can be used to determine whether the population mean rate at 5 CCF of residential water discharged by U.S public utilities differs from $21.62
H0 : <em> u </em>= 21.62 ( Null hypothesis )
H1 : <em> u</em> = 21.62 ( alternative hypothesis )
