Answer:
x=5 and y=2
Step-by-step explanation:
I hope this helps
The answer is 50625 because 5*3 is 15 and take that to the power of 4
All three series converge, so the answer is D.
The common ratios for each sequence are (I) -1/9, (II) -1/10, and (III) -1/3.
Consider a geometric sequence with the first term <em>a</em> and common ratio |<em>r</em>| < 1. Then the <em>n</em>-th partial sum (the sum of the first <em>n</em> terms) of the sequence is
Multiply both sides by <em>r</em> :
Subtract the latter sum from the first, which eliminates all but the first and last terms:
Solve for :
Then as gets arbitrarily large, the term will converge to 0, leaving us with
So the given series converge to
(I) -243/(1 + 1/9) = -2187/10
(II) -1.1/(1 + 1/10) = -1
(III) 27/(1 + 1/3) = 18
Answer:
13 < n < 51
Explanation:
Basically to find the lowest possible length, all you need to do is subtract the lower number from the higher number (32 - 19), and to find the greatest possible length, add the lower number and the higher number (32 + 19). Then you'd plug it in to this inequality: a < n < b, a being the difference, and b being the sum. But, if the triangle were a right triangle that would be a whole different story.