Answer:
Explanation:
From the given information:
The equation for the reaction can be represented as:
The I.C.E table can be represented as:
2SO₂ O₂ 2SO₃
Initial: 14 2.6 0
Change: -2x -x +2x
Equilibrium: 14 - 2x 2.6 - x 2x
However, Since the amount of sulfur trioxide gas to be 1.6 mol.
SO₃ = 2x,
then x = 1.6/2
x = 0.8 mol
For 2SO₂; we have 14 - 2x
= 14 - 2(0.8)
= 14 - 1.6
= 12.4 mol
For O₂; we have 2.6 - x
= 2.6 - 1.6
= 1.0 mol
Thus;
[SO₂] = moles / volume = ( 12.4/50) = 0.248 M ,
[O₂] = 1/50 = 0.02 M ,
[SO₃] = 1.6/50 = 0.032 M
Kc = [SO₃]² / [SO₂]² [O₂]
= ( 0.032²) / ( 0.248² x 0.02)
= 0.8325
Recall that; the equilibrium constant for the reaction = 0.8325;
If we want to find:
Then:
Since no temperature is given to use in the question, it will be impossible to find the final temperature of the mixture.
By applying the Boyle's equation and substituting our given data the volume of the container was found to be 418.14 Litres
<h3>
Boyle's Law</h3>
Given Data
- number of moles of Ne = 5.1169 mol
We know that the relationship between pressure and temperature is given as
PV = nRT
R = 0.08206
Making the volume subject of formula we have
V= nRT/P
Substituting our given data to find the volume we have
V = 5.1169*0.08206*911/0.9148
V = 382.522353554/0.9148
V = 418.14 L
Learn more about Boyle's law here:
brainly.com/question/469270
Data:
Arsenic Molar Mass = 74,9216 ≈ 75 u (<span>atomic mass unit)</span>
Solving:
1 mole of arsenic → 75g ------------ 6,02*10²³ molecules
..................................X -------------- 1 molecule
6,02*10²³X = 75
Answer:
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Explanation:
The Hidden Values of Volunteering
Learn New Skills. One fantastic thing that volunteering can offer you is a new understanding of your own abilities. ...
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Accomplish Something Important.
HOPE THIS HELPED ❤✨
Answer:
Explanation: There are 2 moles of C6H12O6 in 300 g C6H12O6 , rounded to one significant figure.