Grouping is when you have to terms that are the same inside the parenthesis and a different or same number outside the parenthesis and then the one inside the parenthesis u are going to group them not combined them and write them once and the numbers inside the parenthesis group them together by adding them and put parenthesis between them
Ex
5(4x+1)10(4x+1)
(5+10)(4x+1)
The answer is 10 as the diameter because it says to estimate pi as 3. Since we know the circumference is 30 we can reverse it to find the diameter, since Circumference is pi time diameter.
Amount of money Aisha receive from selling all of the bracelets is $33.25.
<u>Step-by-step explanation:</u>
In this question, its given that Aisha made bracelets for a craft fair. She spent $29.75 on supplies to make the bracelets. Each bracelet cost her about $0.85 to make. Aisha sells each bracelet for $0.10 more than it cost her to make. Let's calculate Number of bracelets Aisha made as .
Number =
⇒ Number =
⇒ Number =
⇒ Number =
Now , its given that Aisha sell these bracelets with $0.10 more then it cost her i.e. at $0.95 , Let's calculate selling price as :
Price =
Price = $33.25
Therefore, amount of money Aisha receive from selling all of the bracelets is $33.25.
Answer:
We can define a horizontal dilation/contraction of scale factor A, as:
g(x) = f(x*A)
if A > 1, this will be a contraction (it will be steeper)
if 0 < A < 1, this will be a dilation. (it will be less steep)
Then if we have:
g(x) = f(6*x) we have a contraction of scale factor 6, this means that the graph of the parent function will be contracted.
Below, you can see how the graphs change, where:
Blue is f(x) =x
green is g(x) = f(6*x) = 6*x
Answer:
(-16.494 ; -3.506)
Step-by-step explanation:
student Prob A Prob B difference, d (A-B)
1 20 35____ - 15
2 30 40 ___ - 10
3 15 20 ___ - 5
4 40 50 __ - 10
Difference, d = -15, -10, -5, -10
Xd = Σd/ n = - 40 / 4 = - 10
Standard deviation of d ; Sd = 4.082
The confidence interval for the difference is given as :
Xd ± Tcritical*(Sd/√n)
Tcritical at 95%; df = n - 1 ; 4 - 1 = 3
Tcritical(0.05, 3)). = 3.182
C.I = -10 ± 3.182(4.082/√4)
C.I = -10 ± 6.494462
C. I = (-16.494 ; -3.506)