Answer:
9.01%
Explanation:
The following data were obtained from the question:
Mass of sodium nitrate, NaNO3 = 56.5g
Mass of solution = 627g
The percentage composition of sodium nitrate, NaNO3 in the solution can be obtained as follow:
Percentage composition of NaNO3 = Mass of NaNO3/mass of solution x 100
Percentage composition of NaNO3 = 56.5/627 x 100 = 9.01%
Therefore, the percentage composition of sodium nitrate, NaNO3 in the solution is 9.01%
Answer:
Mass of 
produced = 32 g
Explanation:
Calculation of the moles of 
as:-
Mass = 82.4 g
Molar mass of = 122.55 g/mol
The formula for the calculation of moles is shown below:
Thus,
From the reaction shown below:-
2 moles of potassium chlorate on reaction forms 3 moles of oxygen gas
So,
0.67237 moles of potassium chlorate on reaction forms 
moles of oxygen gas
Moles of oxygen gas = 1 mole
Molar mass of oxygen gas = 32 g/mol
<u>Mass of produced = 32 g</u>
Because dalton had the facts from other's experiments. Democritus just had an unproven theory.
53 pounds divided by 2.2 kilograms to get the converted weight
which is 24.09 kilograms. Round this off to 24 kgs. 10 mg/kg multiply this to
24 kg, it would be 240 mg. 240 mg divided by 80 is 3. Therefore, a 53−lb child
requires to have a dosage of 3 tablets.
Electrons orbit and the protons and neutrons are in the nucleus
