Here's what I got for the first question.
Did you want answers for the second one? I couldn't read that part of the image very well, if you did.
Answer:
Step-by-step explanation:
Suppose we think of an alphabet X to be the Event of the evidence.
Also, if Y be the Event of cheating; &
Y' be the Event of not involved in cheating
From the given information:
Thus, 
P(Y') = 1 - 0.01
P(Y') = 0.99
The probability of cheating & the evidence is present is = P(YX)
The probabilities of not involved in cheating & the evidence are present is:
(b)
The required probability that the evidence is present is:
P(YX or Y'X) = 0.006 + 0.000099
P(YX or Y'X) = 0.006099
(c)
The required probability that (S) cheat provided the evidence being present is:
Using Bayes Theorem
Answer:
B
Step-by-step explanation:
Let's say that the smallest is called "a"
We can re-write the question like this:
a+(a+1)+(a+2)+(a+3) = 174
4a+6=174
4a=168
a=42
I believe the answer should be graph J
All of my teachers have told me that everyone remembers things best in groups of seven. so I would suggest to pick a continent and start in a corner and spend a couple of days studying seven countries in that area. also quiz your self every once in a while for extra help.
I hope this helps you
