4 of 9
so 4/9 = 0.44444444444444444444444444444repeating
(sorry, not sure how to get bar notation for that)
Answer:
The sampling distribution of is: .
Step-by-step explanation:
According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.
The mean of this sampling distribution of sample proportion is:
The standard deviation of this sampling distribution of sample proportion is:
The study was conducted using the data from 15,000 students.
Since the sample size is so large, i.e. <em>n</em> = 15000 > 30, the central limit theorem is applicable to approximate the sampling distribution of sample proportions.
So, the sampling distribution of is: .
Answer:
1/4
Step-by-step explanation:
.25 out of 1.0
.25*4=1
Glad I could help!
Answer:
$1.95
Step-by-step explanation:
notebook = n
pencil = p
3n + 2p = 5.10
2n + 3p = 4.65
multiply top equation by 2 and bottom by 3
6n + 4p = 10.20
6n +9p = 13.95
subtract bottom equation from the top equation
-5p = -3.75
divide by 5, negatives cancel out
p = 0.75
sub p into either equation, I chose the original top equation
3n + 2(0.75) = 5.10
3n + 1.50 = 5.10
subtract 1.50 from both sides
3n = 3.60
divide both sides by 3
n = 1.20
p = 0.75
n + p = 1.95 (the fourth option)
The gcf of 15 and 10 is 5