Answer: c. 39.14 to 42.36
Step-by-step explanation:
We want to determine a 95% confidence interval for the average hourly wage (in $) of all information system managers
Number of sample, n = 75
Mean, u = $40.75
Standard deviation, s = $7.00
For a confidence level of 95%, the corresponding z value is 1.96. This is determined from the normal distribution table.
We will apply the formula
Confidence interval
= mean +/- z ×standard deviation/√n
It becomes
40.75 +/- 1.96 × 7/√75
= 40.75 ± 1.96 × 0.82
= 40.75 + 1.6072
The lower end of the confidence interval is 40.75 - 1.6072 =39.14
The upper end of the confidence interval is 40.75 + 1.6072 =42.36
Answer:
2000 cm^2/min
Step-by-step explanation:
According to the given question,
12 m^2/h = ? cm^2/min
We know,
1 h = 60 min and 1 m = 100 cm
So, by putting the values we get
- 12 m^2/h = 12 × (100)^2/60
Thus the answer of the given question is 2000 cm^2/min .
Exclusive events, for OR we can add probabilities.
P(O or B) = 0.49 + 0.20 = 0.69
Answer 0.69
The formula for the future value of the account is
A = P(1 + r/n)^(nt)
where you have
A = 19909.20
P = 8975
r = 0.038
t = 21
The resulting equation is not one that can be solved by algebraic means, but we can use a graphing calculator to find n. This graph shows us n = 12, so
the interest compounds monthly.
Answer:
the y-intercept is (0,75)
Step-by-step explanation:
the y-intercept is where the line crosses the y-axis.