Find the magnitude of the electric force on a 2.0 uC charge in a 100n/C electric field.

Physics

1 answer:

Eva8 [605]2 years ago

4 0

Answer:

Electric force will be equal to $2\times 10^{-4}N$

Explanation:

We have given charge $q=2\mu C=2\times 10^{-6}C$

Electric field will be $E=100N/C$

We have to find the magnitude of force

Electric force is the multiplication of electric field and charge

So electric force $F=qE=2\times 10^{-6}\times 100=2\times 10^{-4}N$

Electric force will be equal to $2\times 10^{-4}N$

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