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2 years ago

How many solutions does 2x+ 2x+ 2=4+2x have

1 answer:

3 0

Let's see!
$2x + 2x + 2 = 4 + 2x\\ 4x + 2 = 4 + 2x\\ 4x - 2x + 2 = 4 + 2x - 2x\\ 2x + 2 = 4\\ 2x + 2 - 2 = 4 - 2\\ 2x + 0 = 2\\ 2x = 2\\ 2x/2 = 2/2\\ x = 1\\$
The answer is B

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How to solve 2/3x-36>22

Sonja [21]

Answer:

Step-by-step explanation:

2/3x-36 > 22

Multiple each term by 3

3(2/3x-36) > 3(22)

2x - 108 > 66

Collecting like terms

2x > 66 + 108

2x > 174

x > 174/2

x > 87

8 0

2 years ago

Evaluate 2(x - 4) + 3x - x2 for x = 2. O A. -6 O B. -2 O C. 6 O D. 2

Olenka [21]

Answer:

B. -2

Step-by-step explanation:

2(x - 4) + 3x - x2

2(2 - 4) + 3(2) - (2)2

2(-2) + 6 - 4

-4 + 6 - 4

-8 + 6

-2

8 0

2 years ago

Rata-rata markah matematik untuk Amin, azman dan aziz adalah 73. Tanda Azman lebih 35 berbanding Amin manakala aziz dua kali gan

vagabundo [1.1K]

Answer:

The Amin's score in math was 46.

Step-by-step explanation:

The question is:

The average math score for Amin, azman and aziz is 73. Azman marks 35 more than Amin while aziz is twice that of Amun. What is Amin's sign?

Solution:

Let us denote that:

x = Amin's score in math

y = Azman's score in math

z = Aziz's score in math.

The average of x, y and z is, 73.

That is:

$\frac{x+y+z}{3}=73\\\\\Rightarrow x+y+z = 219$

Now it is provided that:

$y=x+35...(i)\\z=2x...(ii)$

Use the equations (i) and (ii) to determine the value of x as follows:

$x+y+z=219\\\\x+x+35+2x=219\\\\4x=184\\\\x=46$

Thus, the Amin's score in math was 46.

6 0

2 years ago

A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters

In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

$\Rightarrow y=\sqrt{x^2+100}$

Differentiating with respect to t

$\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}$

$\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}$

Since the car driving towards the intersection at 13 m/s.

so, $\frac{dx}{dt}=-13$

$\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)$

Now

$\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)$

$=\frac{24\times (-13)}{\sqrt{676}}$

$=\frac{24\times (-13)}{26}$

= -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

8 0

2 years ago

14(0.89)^x+4.5 =162

lisabon 2012 [21]

$14(0.89)^{x + 4.5} = 162$
$\frac{14(0.89)^{x + 4.5}}{14} = \frac{162}{14}$
$0.89^{x + 4.5} = 11\frac{4}{7}$
$ln(0.89^{x + 4.5}) = ln(11\frac{4}{7})$
$(x + 4.5)ln(0.89) = ln(11\frac{4}{7})$
$\frac{(x + 4.5)ln(0.89)}{ln(0.89)} = \frac{ln(11\frac{4}{7})}{ln(0.89)}$
$x + 4.5 = -2101.14032500$
$x = 2105.64032500$

3 0

2 years ago