The answer is -1/16 or -0.0625, do you need to see work?
Answer:
Lets solve = 3/5 ÷ 1/2
3/5 ÷ 1/2
= 3/5 × 2/1
= 3 × 2/5 × 1
= 6/5
In mixed fraction its
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Now lets solve "a" option
3/5 × 2
= 3 × 2/5 × 1
= 6/5
In mixed fraction
So option a = 3/5 x 2/1 is ur answer
For Data Set B, we see that the data is more varied. The absolute deviations are 4, 3, 2, 5. The average of these absolute deviations is 3.5. MAD_B = (4+3+2+5)/4 =3.5 M ADB
Hence, The average of these absolute deviations is 3.5.
Answer:
0.05
Step-by-step explanation:
We can correctly state that the total sample space= 100 students
40% of 100 students exercise regularly
The probability that 5 students
Picked at random exercise regularly is
Pr(5) = 5/100= 1/20
Pr(5)= 0.05
