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2 years ago

If AB = 10, BD = 5, and DE= 12, what is the length of BC?

Mathematics

1 answer:

FrozenT [24]2 years ago

4 0

Answer:

BC = 24

Step-by-step explanation:

In the picture attached, the missing triangles are shown:

Data

AB = 10

BD = 5

DE= 12

Then, AD = 10-5 = 5

As a consequence of the "Side Splitter" Theorem:

AD/DE = AB/BC

Replacing with data and solving for BC

5/12 = 10/BC

BC = 10*12/5 = 24

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Find the volume and surface area of the composite figure. Give your answer in terms of π.

irakobra [83]

Answer:

V = 240π cm^3 , S= 168π cm^2

Step-by-step explanation:

The given figure is a combination of hemi-sphere and a cone

Volume:

For volume

r = 6 cm

h = 8 cm

$Volume\ of\ cone = \frac{1}{3}\pi r^2h\\= \frac{1}{3}\pi (6)^2*8\\=\frac{1}{3}\pi *36*8\\=\frac{288}{3}\pi\\=96\pi cm^3 \\\\Volume\ of\ hemisphere = \frac{2}{3}\pi r^3\\=\frac{2}{3}*\pi * (6)^3\\=\frac{2}{3}*\pi *216\\=\frac{432}{3}\\=144\pi cm^3 \\\\Total\ Volume= Volume\ of\ cone + Volume\ of\ hemisphere\\= 96\pi +144\pi \\=240\pi cm^3$

Surface Area:

For this particular figure we have to consider the lateral area of the cone shape and surface area of the hemisphere

We have to find the lateral height

$l = \sqrt{r^2+h^2}\\ l = \sqrt{(6)^2+(8)^2} \\l= \sqrt{36+64}\\ l = \sqrt{100}\\l = 10cm\\\\Surface\ area\ of\ cone = \pi rl\\= \pi (6)(10)\\=\pi *60\\=60 \pi\ cm^2\\\\Surface\ area\ of\ hemisphere = 2\pi r^2\\= 2 \pi * (6)\\= 2 \pi *36\\= 72 \pi\ cm^2\\\\Total\ surface\ Area = Surface\ area\ of\ cone + Surface\ area\ of \ hemisphere\\= 60 \pi + 72 \pi\\=132 \pi\ cm^2$

Hence the first option is correct ..

3 0

2 years ago

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marusya05 [52]

Answer:

B.) (0,1)

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sladkih [1.3K]

Answer:

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Step-by-step explanation:

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vitfil [10]

SinA=5root3/10
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2 years ago

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egoroff_w [7]

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