Answer:
615 g
Explanation:
In order to convert from moles of any given substance into grams, we have to use said substance's <em>molar mass</em>, as follows:
- # moles * Molar mass = grams of substance.
Thus, we now <u>calculate the molar mass of beryllium iodide</u>, BeI₂, using the <em>molar masses of the elements</em>:
- Molar Mass of BeI₂ = Molar Mass of Be + (Molar Mass of I)*2 = 262.821 g/mol
Finally we <u>calculate how many grams are there in 2.34 moles of BeI₂</u>:
- 2.34 mol * 262.821 g/mol = 615 g
The molarity of the solution of H₃PO₄ needed to neutralize the KOH solution is 0.35 M
<h3>Balanced equation </h3>
H₃PO₄ + 3KOH —> K₃PO₄ + 3H₂O
From the balanced equation above,
- The mole ratio of the acid, H₃PO₄ (nA) = 1
- The mole ratio of the base, KOH (nB) = 3
<h3>How to determine the molarity of H₃PO₄ </h3>
- Volume of acid, H₃PO₄ (Va) = 10.2 mL
- Molarity of base, Ca(OH)₂ (Mb) = 0.2 M
- Volume of base, Ca(OH)₂ (Vb) = 53.5 mL
- Molarity of acid, H₃PO₄ (Ma) =?
MaVa / MbVb = nA / nB
(Ma × 10.2) / (0.2 × 53.5) = 1 / 3
(Ma × 10.2) / 10.7 = 1 / 3
Cross multiply
Ma × 10.2 × 3 = 10.7
Ma × 30.6 = 10.7
Divide both side by 30.6
Ma = 10.7 / 30.6
Ma = 0.35 M
Learn more about titration:
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773.33 degrees F
F=Fahrenheit
K=Kelvin
F=K x 9/5 - 459.67
773.33 = 685 x 9/5 - 459.67
The ball travels 10m/s
Speed = distance/time
