The solubility of in grams per litre is .
Further explanation:
Solubility product constant:
It is the equilibrium constant for the reaction that comes into play when an ionic compound is dissolved to produce its respective ions. It is represented by . Consider to be an ionic compound. Its dissociation occurs as follows:
The expression for its is as follows:
Here,
is the solubility product constant.
is the concentration of ions.
is the concentration of ions.
The relation between pH and pOH of the solution is given by the following formula:
...... (1)
Rearrange equation (1) to calculate the pOH of the solution.
...... (2)
The value of pH is 7. Substitute this value in equation (2).
The expression for pOH is as follows:
...... (3)
Rearrange equation (3) for .
...... (4)
The value of pOH is 7. Substitute this value in equation (4).
The dissociation reaction of is as follows:
Let us consider the solubility of be s. Therefore, after dissociation, the concentration of and are s and respectively.
The formula to calculate the molar solubility of is as follows:
…… (5)
Substitute s for , for and for in equation (5).
Solve for s,
Therefore the solubility of comes out to be .
The formula to calculate the solubility of in g/L is as follows:
…… (6)
Substitute for solubility and 88.95 g/mol in equation (6).
Learn more:
- Sort the solubility of gas will increase or decrease: brainly.com/question/2802008.
- What is the pressure of the gas? brainly.com/question/6340739.
Answer details:
Grade: School School
Subject: Chemistry
Chapter: Chemical equilibrium
Keywords: solubility, Mn2+, 2OH-, Mn(OH)2, Ksp, solubility product, molar mass, 88.95 g/mol, 0.002001 g/L.