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2 years ago

1 QUESTION QUICKK EXPERTS/ACE OR ANYONE WHO WANTS TO HELP!!

Mathematics

1 answer:

solniwko [45]2 years ago

8 0

looks like all the statements are true,

Leighanne started at $15, they don't show a 0 for Martin

Martins 1st week is $65

leighanne, is saving 50 per week

leighanne is saving 50 per week, Martin is saving 40 per week

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A nutritionist would like to estimate the number of times adults exercise each week. To collect information, the nutritionist em

enot [183]

Answer:

Step-by-step explanation:

7 0

2 years ago

The answer, and work shown.

hoa [83]

Slope= 1/2
Y intercept= (0,2)

Explanation:
Slope-intercept form is y=mx+b
-2x+4y=8
-8-2x=-4y
Divide by -4
2+1/2x=y

Y=1/2x+2

5 0

2 years ago

A gas is said to be compressed adiabatically if there is no gain or loss of heat. When such a gas is diatomic (has two atoms per

Tems11 [23]

Answer:

The pressure is changing at $\frac{dP}{dt}=3.68$

Step-by-step explanation:

Suppose we have two quantities, which are connected to each other and both changing with time. A related rate problem is a problem in which we know the rate of change of one of the quantities and want to find the rate of change of the other quantity.

We know that the volume is decreasing at the rate of $\frac{dV}{dt}=-4 \:{\frac{cm^3}{min}}$ and we want to find at what rate is the pressure changing.

The equation that model this situation is

$PV^{1.4}=k$

Differentiate both sides with respect to time t.

$\frac{d}{dt}(PV^{1.4})= \frac{d}{dt}k\\$

The Product rule tells us how to differentiate expressions that are the product of two other, more basic, expressions:

$\frac{d}{{dx}}\left( {f\left( x \right)g\left( x \right)} \right) = f\left( x \right)\frac{d}{{dx}}g\left( x \right) + \frac{d}{{dx}}f\left( x \right)g\left( x \right)$

Apply this rule to our expression we get

$V^{1.4}\cdot \frac{dP}{dt}+1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}=0$

Solve for $\frac{dP}{dt}$

$V^{1.4}\cdot \frac{dP}{dt}=-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}\\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}}{V^{1.4}} \\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}$

when P = 23 kg/cm2, V = 35 cm3, and $\frac{dV}{dt}=-4 \:{\frac{cm^3}{min}}$ this becomes

$\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}\\\\\frac{dP}{dt}=\frac{-1.4\cdot 23 \cdot -4}{35}}\\\\\frac{dP}{dt}=3.68$

The pressure is changing at $\frac{dP}{dt}=3.68$ .

7 0

3 years ago

Given f(x)=20x+11, find f(4)

kakasveta [241]

Answer:

Step-by-step explanation:

Substitute 4 in place of x

f(4)=20*4+11

f(4)=80+11

f(4)=91

3 0

2 years ago

Which of the following best explains why one graph appears skewed and one graph appears symmetric? the intervals on the x-axis o

LenKa [72]

The reason for one graph appears skewed, and one graph appears symmetric is the interval on the x-axis of the histogram is inconsistent.

<h3>What is histogram?</h3>

A histogram is the way of representation of data which is used to show the frequency distribution using the rectangle similar to a bar graph.

In the problem, the data given as,

In the attached image below, the histogram and box plot is shown for the ages of Elizabeth's Grandchildren and their frequency.
In the 3rd and 4the bar of histogram, the data is jumped from 14 to 20 instead of 15.
The frequency distribution in histogram for this data is inconsistent.
This inconsistency brought the between the two graphs.

Thus, the reason of one graph appears skewed, and one graph appears symmetric is the interval on the x-axis of the histogram is inconsistent.

Learn more about the histogram here;

brainly.com/question/2962546

5 0

1 year ago