Extensive hydrogen bonding.
It takes a lot of energy to break hydrogen bonds and turn liquid water into a gas, therefore the boiling point for water is high.
Malonate is an aggressive inhibitor of succinate dehydrogenase. If malonate is added to a mitochondrial education this is oxidizing pyruvate as a substrate, it is lower in attention<u> </u><u>Fumarate</u><u>.</u>
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Succinate dehydrogenase is also known as mitochondrial complicated II, and inhibition of succinate dehydrogenase by means of dimethyl malonate has been said to suppress the production of pro-inflammatory cytokines.
Fumaric acid is an organic compound with the system HO₂CCH=CHCO₂H. It has a fruit-like taste and has been used as a meal additive. . The salts and esters are referred to as fumarates. Fumarate also can consult with the C ₄H ₂O²⁻ ₄ ion.
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Answer:
= 0.030 M
Explanation:
We can take x to be the concentration in mol/L of Ag2SO4 that dissolves
Therefore; concentration of Ag+ is 2x mol/L and that of SO4^2- x mol/L.
Ksp = 1.4 x 10^-5
Ksp = [Ag+]^2 [SO42-]
= (2x)^2(x)
= 4x^3
Thus;
4x^3 = 1.4 x 10^-5
= 0.015 M
molar solubility = 0.015 M
But;
[Ag+]= 2x
Hence; silver ion concentration is
= 2 x 0.015 M
= 0.030 M
1. B
The positive charge in water is provided by hydrogen, and gold provides the same charge. However, gold is not more reactive than hydrogen so it can not replace it in the compound.
2. In order to balance the equation, you must sure there are equal moles of each element on the left and right side of the equation:
2C₂H₆ + 7O₂ → 4CO₂ + ₆H₂O
3. The number of moles of sodium atoms on the left of the equation must be equal to the number of moles of sodium atoms on the right, as per the law of conservation of mass. The answer is B.
4. C.
A synthesis reaction usually results from single displacement because some element or compound is produced in its pure form
5. B.
The gas being produced is being synthesized.
Answer:
(a) The normal freezing point of water (J·K−1·mol−1) is
(b) The normal boiling point of water (J·K−1·mol−1) is
(c) the chemical potential of water supercooled to −5.0°C exceed that of ice at that temperature is 109J/mole
Explanation:
Lets calculate
(a) - General equation -
= =
→ phases
ΔH → enthalpy of transition
T → temperature transition
=
= ( is the enthalpy of fusion of water)
=
(b)
= ( is the enthalpy of vaporization)
=
(c) =
°° = °°ΔT
°°
= 109J/mole