Given:
The equation of a function is
To find:
The graph of the given function.
Solution:
The vertex form of a parabola is
...(i)
Where, (h,k) is vertex of the parabola.
We have,
...(ii)
From (i) and (ii), we get
The vertex of the parabola is (4,1).
Now, the table of values is
x y
2 5
3 2
4 1
5 2
6 5
Plot these points on a coordinate plane and connect them by a free hand curve.
The graph of given function is shown below.
63degrees
Step-by-step explanation:
there are multiple ways to do this
for one, angle a = angle e (corresponding angles)
angle f + angle e = 180 degrees (angles on a straight line)
angle f = 180 degrees - angle e where angle e = angle a = 117degrees
so angle f = 63 degrees.
Find the b value by plugging in the slope and known coordinates,
-2=0(4)+b
-2= 0+b
-2=b
You can also tell this without calculating since a slope of 0 will always have the same y value. Therefore if (4,-2) is on the line, the y value of the whole line must be -2.
Final answer: y=0x-2, which is y=-2
Detecting...<span>
</span>Your answer would be:
Answer:
m∠ADC = 132°
Step-by-step explanation:
From the figure attached,
By applying sine rule in ΔABD,
sin(∠ADB) =
= 0.74231
m∠ADB =
= 47.92°
≈ 48°
m∠ADC + m∠ADB = 180° [Linear pair of angles]
m∠ADC + 48° = 180°
m∠ADC = 180° - 48°
m∠ADC = 132°