All categories

2 years ago

What is the formula for manganese (ii) fluoride decahydrate? (you may use a * to represent the dot in the formula.)?

2 answers:

4 0

These types of molecules are called hydrates. They have a certain number of moles attached to the salt. Their characteristic is being hygroscopic. That means that when they are exposed to air, they readily solvate.

The formula for Manganese Fluoride Decahydrate will involve the formula Mn, F and H₂O. In ionic form, Manganese is Mn⁺² while fluoride is in F⁻. When they are brought together, their superscripts are 'cross-multiplied' and becomes their respective subscripts. The compound becomes MnF₂. Then, we add the decahydrate which means 10 moles of H₂O. Hence, the formula for Manganese Fluoride Decahydrate is MnF₂*10H₂O.

goblinko [34]2 years ago

3 0

Answer:

MnF₂*10H₂O.

Explanation:

You might be interested in

Mixtures two or more substances that are mixed together but are not chemically combined the substance in a mixture each keep the

sergey [27]

The answer is D, concrete

8 0

2 years ago

Read 2 more answers

Which two elements are combined in sodium chloride

Westkost [7]

Answer:

Sodium (Na) and Chlorine (CI)

Explanation:

6 0

2 years ago

Read 2 more answers

Suppose that you are performing a titration on a monoprotic acid. Titration of this monoprotic acid required a volume of 0.1L of

Alex73 [517]

Answer: A) More base is likely required to reach the endpoint for the diprotic acid than for the monoprotic acid under these conditions

Explanation:

The monoprotic acid (HA) has a valency of 1 and diprotic acid $(H_2A)$ has a valency of 2.

As the concentration and volume of the diprotic acid and the monoprotic acids are equal.

The neutralization reaction for monoprotic acid is:

$HA+BOH\rightarrow BA+H_2O$

The neutralization reaction for diprotic acid is:

$H_2A+2BOH\rightarrow B_2A+2H_2O$

Thus more number of moles of base are required for neutralization of diprotic acid and thus the volume required will be more as concentration and volume of the diprotic acid and the monoprotic acids are equal.

6 0

2 years ago

A lead–tin alloy of composition 30 wt% Sn–70 wt% Pb is slowly heated from a temperature of 150°C (300°F).(a) At what temperature

Novay_Z [31]

Answer:

a) 231.9 °C

b) 100% Sn

c) 327.5 °C

d) 100% Pb

Explanation:

This is a mixture of two solids with different fusion point:

$Tf_{Pb}=327.5 C$

$Tf_{Sn}=231.9 C$

<u>Given that Sn has a lower fusion temperature it will start to melt first at that temperature. </u>

So the first liquid phase forms at 231.9 °C and because Pb starts melting at a higher temperature, that phase's composition will be 100% Sn.

The mixture will be completely melted when you are a the higher melting temperature of all components (in this case Pb), so it will all in liquid phase at 327.5 °C.

At that temperature all Sn was already in liquid state and, therefore, the last solid's composition will be 100% Pb.

3 0

2 years ago

I can't find the density of this question I need help

zaharov [31]

Density is Mass divided by volume.

4 0

3 years ago