Answer:
[see below]
Step-by-step explanation:
Quadrant One has a positive value for both x and y. (+ , +)
Quadrant Two has a negative x value. (- , +)
Quadrant Three has a negative value for both x and y. (- , -)
Quadrant Four has a negative y value. (+, -)
Therefore:
(2, -3) would be plotted in Q4. It does not lie on any axis.
(0, 8) would be on the positive y-axis. (0 is neither negative nor positive.)
(-1, -2) would be plotted in Q3. It does not lie on any axis.
(4, 7) would be plotted in Q1. It does not lie on any axis.
Answer:
see explanation
Step-by-step explanation:
The equation of a parabola in vertex form is
f(x) = a(x - h)² + k
where (h, k) are the coordinates of the vertex and a is a multiplier
f(x) = 2(x - 3)² - 4 ← is in vertex form
with (h, k) = (3, - 4), thus
1 the vertex is (3, - 4 )
Consider the value of a
• If a > 0 then graph opens up and is a minimum
• If a < 0 then graph opens down and is a maximum
2 Here a = 2 thus the graph opens up
The max/ min value of the function is the y- coordinate of the vertex, thus
3 The function has a minimum value of - 4
(x-1)^2-4
If u put the vertex into vertex form you get this answer.
check the picture below.
make sure your calculator is in Degree mode.
Answer
Step-by-step explanation:
mathaway will help !
