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Elena-2011 [213]

2 years ago

6

Midpoint (11,-22) endpoint (17, -19) find the other endpoint

1 answer:

german2 years ago

8 0

Midoint formula

the midoin between (x1,y1) and (x2,y2) is
$( \frac{x1+x2}{2}, \frac{y1+y2}{2})$

midpont=11,-22
endoint is 17,-19

(11,-22)= $( \frac{17+x2}{2}, \frac{-19+y2}{2})$

therfor
11= $\frac{17+x2}{2}$
-22= $\frac{-19+y2}{2}$
solve each
times 2 to both sides of both euations

22=17+x2
-44=-19+y2

minus 17 both sides for first
add 19 both sides for second

5=x2
-25=y2

the other endpoint is (5,-25)

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A pre-algebra book is 8 space 1 half inches by 9 space 1 fourth inches. Determine the perimeter of the textbook

s344n2d4d5 [400]

Rectangular book

two 8 1/2 sides

two 9 1/4 sides

8 1/2*2=17

9 1/4*2=18 1/2

17+18 1/2= 35 1/2

The perimeter of the textbook is 35 1/2 inches or 35.5 inches.

Hope this helps :)

8 0

2 years ago

Floyd is an aspiring music artist. He has a record contract that pays him a base rate of \$200$200dollar sign, 200 a month and a

Vikentia [17]

$644-$200=444
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8 0

2 years ago

Read 2 more answers

A 2000-gallon metal tank to store hazardous materials was bought 15 years ago at cost of $100,000. What will a 5,000-gallon tank

harkovskaia [24]

Answer:

The value is $P_o = \$ 561958.9$

Step-by-step explanation:

From the question we are told that

The capacity of the metal tank is $C = 2000 \ gallon$

The duration usage is $t = 15\ years \ ago$

The cost of 2000-gallon tank 15 years ago is $P = \$100,000$

The capacity of the second tank considered is $C_1 = 5,000$

The power sizing exponent is $e = 0.57$

The initial construction cost index is $u_1 = 180$

The new construction after 15 years cost index is $u_2 =600$

Equation for the power sizing exponent is mathematically represented as

$\frac{P_n}{P} = [\frac{C_1}{C} ]^{e}$

=> Here $P_n$ is the cost of 5,000-gallon tank as at 15 years ago

So

$P_n = [\frac{5000}{2000} ] ^{0.57} * 100000$

$P_n = \$168587.7$

Equation for the cost index exponent is mathematically represented as

$\frac{P_o}{P_n} = \frac{u_2}{u_1}$

Here $P_o$ is the cost of 5,000-gallon tank today

So

$\frac{P_o}{168587.7} = \frac{600}{180}$

=> $P_o = \frac{600}{180} * 168587.7$

=> $P_o = \$ 561958.9$

8 0

2 years ago

What is the solution of the equation sqrt b-17 + sqrt b=1?

Inga [223]

Answer:

no solution.

Step-by-step explanation:

The given equation is

$\sqrt{b-17}+\sqrt{b}=1$

$\mathrm{Subtract\:}\sqrt{b}\mathrm{\:from\:both\:sides}\\\sqrt{b-17}+\sqrt{b}-\sqrt{b}=1-\sqrt{b}$

On simplifying, we get

$\sqrt{b-17}=1-\sqrt{b}$

Squaring both sides

$\left(\sqrt{b-17}\right)^2=\left(1-\sqrt{b}\right)^2\\\\b-17=1-2\sqrt{b}+b$

Subtract b from both sides

$17=1-2\sqrt{b}$

On simplifying, we get

$-18=-2\sqrt{b}$

Squaring both sides

$324=4b\\\\b=81$

Now, we substitute this value in the original equation

$\sqrt{81-17}+\sqrt{81}=1\\\\\sqrt{64}+9=1\\\\8+9=1\\\\17=1\text{ This is False}$

Hence, b = 81 is an extraneous solution.

Therefore, the given equation has no solution.

3 0

2 years ago

Sonbull [250]

Answer:

c

Step-by-step explanation:

7 0

2 years ago