Answer:
True I hope you like it
Give me a brainliest answer
Answer:
770m/s
Explanation:
caculation using one of the newton law of motion
I believe that the answer to this would be B
Hope this helped
The solution you should use is Hooke's law: F=-kx
It should have the same signs because they repel due to the stretch of the spring.
a. Since there is a constant energy within the spring, then Hooke's law will determine the possible algebraic signs. The solution should be
<span>F = kx
270 N/m x 0.38 m = 102.6 N
</span>
b. Then use Coulomb's law; F=kq1q2/r^2 to find the charges produced in the force.