What is the point-slope form of a line with slope -4 that contains the point (-2, 3?
2 answers:
The point-slope equation of a line that cointains the point (x1,y1) and has a slope of m is
y-y1=m(x-x1)
so
point (-2,3) and slope -4
y-3=-4(x-(-2))
y-3=-4(x+2) is da equation
Answer:
y-3=-4(x+2)
Step-by-step explanation:
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diagonal = sqrt(l^ + w^2)
17 = sqrt(10^2 + x^2)
17^2 = 10^2 + x^2
289 = 100 + x^2
189 = x^2
x = sqrt(189) = 13.747
X = 13.75
width is 13.75 inches
Answer:
n=18
Step-by-step explanation:
7n+11?
n=7+11
7+11=18
n=18
<h3>Solution:</h3>
<h3>Answer:</h3>
Usually you use addition to find a sum.
Answer:
B
Step-by-step explanation:
12*12=144
-12*-12=144
16*16=256
-16*-16=256