x^2 + y^2 + 2x - 6y + 1 = 0
x^2 +2x + 1 + y^2 - 6y = 0
x^2 + 2( x × 1) + 1^2 + y^2 - 2(y×3) + 3^2 -3^2 =0
(x+1)^2 + (y-3)^2 = 3^2
comparing with circle equation
(x-a)^2 + (y - b)^2 = r^2
where (a , b) is centre of circle.
so we get center of circle is
(-1, 3)
Answer: 16 ft
Explanation:
You can determine the lengths of each segment by subtracting the coordinates of the adjacent points.
1) From (2,5) to (8,5): 8 - 2 = 6
2) From (8,5) to (8,3): 5 - 3 = 2
3) From (8,3) to (2,3): 8 - 2 = 6 (as expected as this is congruent to the first
4) From (2,3) to (2,5): 5 - 3 = 2 (as expected as this is congruent to the second).
The total length of the border or perimeter is equal to the sum of all the sides:
perimeter = 6 + 2 + 6 + 2 = 16
Therefore the answer is 16 ft
Given:
Uniform distribution of length of classes between 45.0 to 55.0 minutes.
To determine the probability of selecting a class that runs between 51.5 to 51.75 minutes, find the median of the given upper and lower limit first:
45+55/2 = 50
So the highest number of instances is 50-minute class. If the probability of 50 is 0.5, then the probability of length of class between 51.5 to 51.75 minutes is near 0.5, approximately 0.45. <span />
<u>Not sure what you are asking for, but,</u>
<u>Here is an example of a JRU (Join Result Unknown) word problem</u>:
There were _____ kids on the playground. ____ more kids came onto the playground. How many kids are on the playground?
<u>Here is an example of a JCU (Join Change Unknown) word problem:</u>
There were ____ kids on the playground. Some more kids came on the playground. Now there are ____ kids on the playground. How many kids came on the playground?
<u>
Here is an example of a JSU (Join Start Unknown) word problem:</u>
Some kids were on the playground. ____ kids came on the playground. Now there are ____ kids on the playground. How many kids were on the playground at the beginning?
Answer:
y = 24
Step-by-step explanation:
The sum of the angles of a triangle is 180
A+B+C = 180
ABC = 60
We know 2x-4 = 60
2x -4+4 = 60+4
2x = 64
x = 64/2 = 32
A = 3x = 3(32) = 962x-4 = 60
B = 60
Using the first equation
96+ 60 +y = 180
156 +y =180
y = 180-156
y = 24
