Answer:
The answer is "2x-y=4"
Step-by-step explanation:
Given:
The Formula of Slope:
by replacing the (2,0) and (0,-4) coordinates in the above formula:
if point y intercepting in x then x=0, for this the value of x= 0 and c=-4.
Equation of the line:
apply m and c value in the above equation:
Subtract by 2x on both sides of the equation we get:
Answer:
(x-1)^2+(y+19/8)^2=2665/64
Step-by-step explanation:
The general equation of a circle is
(x - h)^2 + (y - k)^2 = r^2
Substituting the values of the 3 given points:
(-5 - h)^2 + (0 - k)^2 = r^2
(0 - h)^2 + (4 - k)^2 = r^2
(2 - h)^2 + (4 -k)^2 = r^2
Subtracting the second equation from the first:
(-5-h)^2 - h^2 + k^2 - (4 - k)^2 = 0
25 + 10h + h^2 - h^2 + k^2 - 16 + 8k - k^2 = 0
10h + 8k = -9 ------------ (A).
Subtract the third equation for the second:
h^2 - (2 - h)^2 + 0 = 0
h^2 - 4 + 4h - h^2 = 0
4h = 4
h = 1.
Substituting for h in equation A:
10 + 8k = -9
8k = -19
k = -19/8
So r^2 = (-5-1)^2 + (0 + 19/8)^2 =
36 + 361/ 64
= 2665/64
Answer:
(-4)³ = -64
(4)⁻³ = 1/64
Step-by-step explanation:
To solve this, you have to know that the first derivative of a function is its slope. When an interval is increasing, it has a positive slope. Thus, we are trying to solve for when the first derivative of a function is positive/negative.
f(x)=2x^3+6x^2-18x+2
f'(x)=6x^2+12x-18
f'(x)=6(x^2+2x-3)
f'(x)=6(x+3)(x-1)
So the zeroes of f'(x) are at x=1, x=-3
Because there is no multiplicity, when the function passes a zero, he y value is changing signs.
Since f'(0)=-18, intervals -3<x<1 is decreasing(because -3<0<1)
Thus, every other portion of the graph is increasing.
Therefore, you get:
Increasing: (negative infinite, -3), (1, infinite)
Decreasing:(-3,1)
