Answer:
but I have a great day of school and the other day
Step-by-step explanation:
- <em><u>H</u></em><em><u> </u></em><em><u>Tu</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>be</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>great</u></em><em><u> </u></em><em><u>day</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>school</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>other</u></em><em><u> </u></em><em><u>day</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>school</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>other</u></em><em><u> </u></em><em><u>day</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>school</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>other</u></em><em><u> </u></em><em><u>day</u></em>
The weight of the kitten will be no less than the weight of the puppy in 1.4 + 1.2x ≥ 2.8 + 0.5x week.
<h3>What is Inequality?</h3>
Statement of an order relationship—greater than, greater than or equal to, less than, or less than or equal to—between two numbers or algebraic expressions.
Given:
A puppy weighs 2.8 pounds at birth and gained about 0.5 pounds per week.
A kitten weighs 1.4 pounds at birth and gains about 1.2 pounds per week.
puppy: 2.8 + 0.5x
Kitten: 1.4 + 1.2x
As, kitten is no less than puppy.
Kitten ≥ puppy
1.4 + 1.2x ≥ 2.8 + 0.5x
hence, the weight of the kitten will be no less than the weight of the puppy in 1.4 + 1.2x ≥ 2.8 + 0.5x week.
Learn more about inequality here:
brainly.com/question/23575974
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3 x 3 = 9 i hope that helps
Question
Marcus asked 10 people at a juggling festival what age they were when they started to juggle. Which interval contains the median age?
Answer:
See Explanation
Step-by-step explanation:
Given
Required
The median interval
The question is incomplete, as the required data is not given.
To solve this question, I will use the following assumed dataset.
First, calculate the median position.
This implies that the median is the mean of the 5th and 6th data
So, we have the interval to be.
<em>Generally, the median of 10 data set is located at interval 5 to 6</em>
Answer:
$493.01
Step-by-step explanation:
463.28 + 28.35 + 78.88 - 77.50