Answer:
i just started sorry but i try uh is hard please don't
Step-by-step explanation:
Answer:
i so want to know this aswell
Step-by-step explanation:
Notice that the 2 expressions have 2 common terms.
(r-s) is just (s-r) times (-1)
similarly
(t-s) is just (s-t) times (-1)
this means that :
(r-s) (t-s) + (s-r) (s-t)=-(s-r)[-(s-t)]+(s-r) (s-t)
the 2 minuses in the first multiplication cancel each other so we have:
-(s-r)[-(s-t)]+(s-r) (s-t)=(s-r) (s-t)+(s-r) (s-t)=2(s-r) (s-t)
Answer:
d)<span>2(s-r) (t-s) </span>
Answer:
Step-by-step explanation:
x² + 6x + 1 = 0
a = 1 , b = 6 , c = 1
Answer:
look it up
Step-by-step explanation: