Answer:
57.8125% or approx. 57.8%
Step-by-step explanation:
There is a 1/4, or 25%, or 0.25 chance that an egg has salmonella.
Thus, there is a 75%, or 0.75 chance that an egg DOESN'T contain salmonella.
Let's find the probability that all 3 of Larry's eggs are free from salmonella. Larry would have to hit that 75% chance 3 times in a row. The chance of that happening is:
0.75 * 0.75 * 0.75 = = 0.421875
From this, we can deduce that if there is a 0.421875 (42.1875%) chance that all eggs are safe to eat, there must be a...
1 - 0.421875 = 0.578125
...0.578125 (57.8125%) chance that 1 or more of Larry's eggs do have salmonella.
Answer: approx. 57.8% or 57.8125%
Answer:
"demand"
Step-by-step explanation:
Vocabulary question.
"Demand" refers to the quantity of goods and services that consumers are willing to buy at a given price.
for 1st
use the formula of inlargement
A(x,y)when enlarging by scale factor k gives A'(kx,ky)
for 2nd
a=
(2a+3)-(a-5)(2a+2)+a^2
b=
3y(7y-8)
Answer:
Step-by-step explanation:
(3x^2+x-1)(x^4-2x+1)
=3x^6-6x^3+3x^2+x^5-2x^2+x-x^4+2x-1
=3x^6+x^5-x^4-6x^3+x^2+3x-1
Hope this helps!! :)
Please let me know if you have any question