17) f(x) = 16/(13-x).
In order to find domain, we need to set denominator expression equal to 0 and solve for x.
And that would be excluded value of domain.
13-x =0
Adding x on both sides, we get
13-x +x = x.
13=x.
Therefore, domain is All real numbers except 13.
18).f(x) = (x-4)(x+9)/(x^2-1).
In order to find the vertical asymptote, set denominator equal to 0 and solve for x.
x^2 -1 = 0
x^2 -1^2 = 0.
Factoring out
(x-1)(x+1) =0.
x-1=0 and x+1 =0.
x=1 and x=-1.
Therefore, Vertical asymptote would be
x=1 and x=-1
19) f(x) = (7x^2-3x-9)/(2x^2-4x+5)
We have degrees of numberator and denominator are same.
Therefore, Horizontal asymptote is the fraction of leading coefficents.
That is 7/2.
20) f(x)=(x^2+3x-2)/(x-2).
The degree of numerator is 2 and degree of denominator is 1.
2>1.
Degree of numerator > degree of denominator .
Therefore, there would no any Horizontal asymptote.
Answer:
4½ km
Step-by-step explanation:
2 cm= 1 km
1 cm= ½ km
4cm×2km = 8cm
8 cm (4 km) + 1 cm (½ km) = 9 cm
9 cm/ 4 ½ km
Answer:
Y=-4x+6
Step-by-step explanation:
Step 1: Add -x to both sides.
X+0.25y+-x=1.5+-x
0.25y=-x+1.5
Step 2: Divide both sides by 0.25.
0.25y/0.25=-x+1.5/0.25
Y=-4x+6
Hope I helped
To solve this you must use the rules of PEMDAS (Parentheses, Exponent, Multiplication, Division, Addition, Subtraction)
In this problem we have double parentheses. Which one should we solve first? The answer to that is always the inner most ones:
13[ 6² ÷ (5² - 4²) + 9]
5² - 4²
^^^Here you will have to first take the square of both values
25 - 16
9
13[ 6² ÷ (9) + 9]
Now for the exponents
13[ 6² ÷ (9) + 9]
6²
36
13[ 36 ÷ 9 + 9]
Now for the division:
13[ 36 ÷ 9 + 9]
36 ÷ 9
4
13[ 4 + 9]
Now for the addition
13[ 4 + 9]
4 + 9
13
13[13]
Now for multiplication
169
Hope this helped!
~Just a girl in love with Shawn Mendes
Ned thought he needed 2/3 cups of flour for his donut recipe, but in order for him to get the correct amount, he needs to divide by 3/4.