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2 years ago

Write Successor of 999 please help me

Mathematics

1 answer:

madam [21]2 years ago

6 0

Answer:

1000

Step-by-step explanation:

The successor of 999 is 1000

999+1=1000

SUCCESSOR

The number which comes immediately after a particular number is called its successor. The successor of a whole number is the number obtained by adding 1 to it. Clearly, the successor of 0 is 1; successor of 1 is 2; successor of 2 is 3 and so on.

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What is the value of x if f(x) = 76

GaryK [48]

Answer:

The roots (zeros) are the x values where the graph intersects the x-axis. To find the roots (zeros), replace f(x) with 0 and solve for x

No solution

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2 years ago

Help please!!! I dont understand these questions currently attaching photos dont delete

Katyanochek1 [597]

Answer:

b/a
16a²b²
n¹⁰/(16m⁶)
y⁸/x¹⁰
m⁷n³n/m

Step-by-step explanation:

These problems make use of three rules of exponents:

$a^ba^c=a^{b+c}\\\\(a^b)^c=a^{bc}\\\\a^{-b}=\dfrac{1}{a^b} \quad\text{or} \quad a^b=\dfrac{1}{a^{-b}}$

In general, you can work the problem by using these rules to compute the exponents of each of the variables (or constants), then arrange the expression so all exponents are positive. (The last problem is slightly different.)

1. There are no "a" variables in the numerator, and the denominator "a" has a positive exponent (1), so we can leave it alone. The exponent of "b" is the difference of numerator and denominator exponents, according to the above rules.

$\dfrac{b^{-2}}{ab^{-3}}=\dfrac{b^{-2-(-3)}}{a}=\dfrac{b}{a}$

2. 1 to any power is still 1. The outer exponent can be "distributed" to each of the terms inside parentheses, then exponents can be made positive by shifting from denominator to numerator.

$\left(\dfrac{1}{4ab}\right)^{-2}=\dfrac{1}{4^{-2}a^{-2}b^{-2}}=16a^2b^2$

3. One way to work this one is to simplify the inside of the parentheses before applying the outside exponent.

$\left(\dfrac{4mn}{m^{-2}n^6}\right)^{-2}=\left(4m^{1-(-2)}n^{1-6}}\right)^{-2}=\left(4m^3n^{-5}}\right)^{-2}\\\\=4^{-2}m^{-6}n^{10}=\dfrac{n^{10}}{16m^6}$

4. This works the same way the previous problem does.

$\left(\dfrac{x^{-4}y}{x^{-9}y^5}\right)^{-2}=\left(x^{-4-(-9)}y^{1-5}\right)^{-2}=\left(x^{5}y^{-4}\right)^{-2}\\\\=x^{-10}y^{8}=\dfrac{y^8}{x^{10}}$

5. In this problem, you're only asked to eliminate the one negative exponent. That is done by moving the factor to the numerator, changing the sign of the exponent.

$\dfrac{m^7n^3}{mn^{-1}}=\dfrac{m^7n^3n}{m}$

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2 years ago

26 ptss!! select the expressions that are equivalent to the expression below.

valkas [14]

Answer:

1st, 2nd, and last.

Step-by-step explanation:

For the first two common rules can be applied such as $n\sqrt{a/b}$ = $\frac{\sqrt[n]{a} }{\sqrt[n]{b} }$ and that $\sqrt[n]{\frac{a}{b} } = (\frac{a}{b})^{n}$

and for the last one this is just simplifying the radical and if you factor it you realize that, $\frac{750}{512} = \frac{5^3}{8^3}*6$ meaning that you can take the radical off of 5/8 and end up with that final answer

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2 years ago

The polynomial p(x)=x^3-6x^2+32p(x)=x 3 −6x 2 +32p, left parenthesis, x, right parenthesis, equals, x, cubed, minus, 6, x, squar

Ray Of Light [21]

Answer:

(x-4)(x-4)(x+2)

Step-by-step explanation:

Given p(x) = x^3-6x^2+32 when it is divided by x - 4, the quotient gives

x^2-2x-8

Q(x) = P(x)/d(x)

x^3-6x^2+32/x- 4 = x^2-2x-8

Factorizing the quotient

x^2-2x-8

x^2-4x+2x-8

x(x-4)+2(x-4)

(x-4)(x+2)

Hence the polynomial as a product if linear terms is (x-4)(x-4)(x+2)

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2 years ago

Find the measure of angle x.

Bezzdna [24]

Answer:The measure of angle x is 65°.

Step-by-step explanation: Determine the measure of angle x. Step 1: Add together the known angles. Step 2: Subtract the sum from 180°. The measure of angle x is 65°.

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2 years ago

Write Successor of 999 please help me ​

Write Successor of 999 please help me