Answer:
a. 3
b. 5
c. 4
d. 4
e. 10
Step-by-step explanation:
<span>Use a proportion:
x/(5 1/2) = 50/4
--------
x = (11/2)(50/4)
--------
x = 550/8
----
x = $68.75</span>
For this case, we perform the conversions:
First roll:
We make a rule of three to determine the number of "c" boxes that can be packed with 300 meters of adhesive tape.
1 -----------> 4.2
c -----------> 300
You can pack 71 boxes.
Second roll:
We make a rule of three to determine the number of "c" boxes that can be packed with 70 meters of adhesive tape.
1 -----------> 4.2
c -----------> 70
You can pack 16 boxes.
Third roll:
1 -----------> 4.2
c -----------> 50
You can pack 11 boxes.
Thus, in total you can pack
Answer:
98 boxes
Answer:
The answer to your question is ( -7/10, -4 7/10)
Step-by-step explanation:
Data
Enpoint (3/2, 1 1/2) x1 = 3/2 y1 = 1 1/2
Midpoint (2/5, -8/5) xm = 2/5 ym = -8/5
Entpoint 2 ( x, y)
Formula
Xm = (x1 + x2)/2 Solve for x2 x2 = 2xm - x1
Ym = (y1 + y2)/2 Solve for y2 y2 = 2ym - y1
Substitution
x2 = 2(2/5) - 3/2
x2 = 4/5 - 3/2
x2 = (8 - 15)/10
x2 = -7/10
y2 = 2(-8/5) - 1 1/2
y2 = -16/5 - 3/2
y2 = (-32 - 15) / 10
y2 = -47/10 = -4 7/10
Dimes= $0.10
Nickels=$0.05
$1.10 could hold 11 dimes or 22 nickels, but there on only 15 coins are in this total.
So a total of 7 dimes and 8 nickels is 15 coins and equal to $1.10