Answer:
Step-by-step explanation:
we want to figure out the general term of the following recurrence relation
we are given a linear homogeneous recurrence relation which degree is 2. In order to find the general term ,we need to make it a characteristic equation i.e
the steps for solving a linear homogeneous recurrence relation are as follows:
- Create the characteristic equation by moving every term to the left-hand side, set equal to zero.
- Solve the polynomial by factoring or the quadratic formula.
- Determine the form for each solution: distinct roots, repeated roots, or complex roots.
- Use initial conditions to find coefficients using systems of equations or matrices.
Step-1:Create the characteristic equation
Step-2:Solve the polynomial by factoring
factor the quadratic:
solve for x:
Step-3:Determine the form for each solution
since we've two distinct roots,we'd utilize the following formula:
so substitute the roots we got:
Step-4:Use initial conditions to find coefficients using systems of equations
create the system of equation:
solve the system of equation which yields:
finally substitute:
and we're done!
Answer:
Minus each number to figure out the common difference which is -4.
54-4= 50
50-4= 46
46-4= 42
42-4= 38
The set of ordered pairs (1, 7), (3, 8), (3, 6), (6, 5), (2, 11), (1, 4) represents a relation. Is the relation a function?
Vladimir [108]
Answer:
Step-by-step explanation:
This relation is not a function because the x value repeats. (3,8) and (3,6)
If you plot these points, they won't past the vertical line test
See diagram
totalarea=totallengtht times totalwidth=(2a+5) times (2a+7)=4a²+24a+35
minus original aera
which is 5 by 7 which is 35
4a²+24a+35-35=4a²+24a
3rd option I think, can't tell which is which