What is the slope of a horizontal line?

An airplane on autopilot took 5 hours to travel 3,475 kilometers, what is the unit rate?

tia_tia [17]

Km/h kilometre per hour

8 0

1 year ago

Help and explain explain !!!!!!!!!!

tigry1 [53]

Answer:

$x=-1\text{ or }x=11$

Step-by-step explanation:

For $a=|b|$ , we have two cases:

$\begin{cases}a=b,\\a=-b\end{cases}$

Therefore, for $18=|15-3x|$ , we have the following cases:

$\begin{cases}18=15-3x,\\18=-(15-3x)\end{cases}$

Solving, we have:

$\begin{cases}18=15-3x, -3x=3, x=\boxed{-1},\\18=-(15-3x), 18=-15+3x, 33=3x, x=\boxed{11}\end{cases}$ .

Therefore,

$\implies \boxed{x=-1\text{ or }x=11}$

3 0

2 years ago

Have many times does 246 go into 6

eduard

None. If you think about it, 246 is greater than 6, so how can fit 246 into 6? Think about it this way . . how many times can you fit an elephant into a garden hose? . . yeah . . you probably can't . . try reposting your question . . and try making more sense of it next time. :)

8 0

2 years ago

Read 2 more answers

Construct the confidence interval for the population mean mu. c = 0.90, x = 16.9, s = 9.0, and n = 45. A 90% confidence inte

Georgia [21]

Answer:

The 90% confidence interval for population mean is $14.7 < \mu < 19.1$

Step-by-step explanation:

From the question we are told that

The sample mean is $\= x = 16.9$

The confidence level is $C = 0.90$

The sample size is $n = 45$

The standard deviation

Now given that the confidence level is 0.90 the level of significance is mathematically evaluated as

$\alpha = 1-0.90$

$\alpha = 0.10$

Next we obtain the critical value of $\frac{\alpha }{2}$ from the standardized normal distribution table. The values is $Z_{\frac{\alpha }{2} } = 1.645$

The reason we are obtaining critical values for $\frac{\alpha }{2}$ instead of that of $\alpha$ is because $\alpha$ represents the area under the normal curve where the confidence level 1 - $\alpha$ (90%) did not cover which include both the left and right tail while $\frac{\alpha }{2}$ is just considering the area of one tail which is what we required calculate the margin of error