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2 years ago

15

If you knew that the vertical intercept for a straight line was 15, that the slope was -.5, and that the independent variable ha

d a value of 8, the value of the dependent variable would be:

1 answer:

Finger [1]2 years ago

7 0

Y=-.5x+15 plug in 8 for x and you get 11

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401 ft

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2 years ago

I need help. It's kinda hard for me. We have to use decimal numbers

cestrela7 [59]

Answer: 2.4 + 7.6 = 10

Step-by-step explanation:

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2 years ago

If f(x)=3x and g(x)=1/x what is the domain of (gof)(x)?

melomori [17]

Answer:

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Step-by-step explanation:

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2 years ago

Iteration - Maths Question attached

Ivanshal [37]

Answer:

7.8

Step-by-step explanation:

First I will try 50. I got 127,550, so that was way too big.

Let me try a smaller number. How about 5. I got 155, so that was a bit too small.

Now I'll try 20. I got 8420. Looks like the number is between 5 and 20.

How about 7. I got 399.

Let me try 8. I got 584! That's really close. It's just a little too big.

I tried 7.5, and got 485.624. So close! Just a little higher.

Putting in 7.8 yields <u>543.192!</u> That's our answer.

8 0

2 years ago

Rom4ik [11]

Answer:

Part 1) The domain of the quadratic function is the interval (-∞,∞)

Part 2) The range is the interval (-∞,1]

Step-by-step explanation:

we have

$f(x)=-x^2+14x-48$

This is a quadratic equation (vertical parabola) open downward (the leading coefficient is negative)

step 1

Find the domain

The domain of a function is the set of all possible values of x

The domain of the quadratic function is the interval

(-∞,∞)

All real numbers

step 2

Find the range

The range of a function is the complete set of all possible resulting values of y, after we have substituted the domain.

we have a vertical parabola open downward

The vertex is a maximum

Let

(h,k) the vertex of the parabola

so

The range is the interval

(-∞,k]

Find the vertex

$f(x)=-x^2+14x-48$

Factor -1 the leading coefficient

$f(x)=-(x^2-14x)-48$

Complete the square

$f(x)=-(x^2-14x+49)-48+49$

$f(x)=-(x^2-14x+49)+1$

Rewrite as perfect squares

$f(x)=-(x-7)^2+1$

The vertex is the point (7,1)

therefore

The range is the interval

(-∞,1]

6 0

2 years ago