Answer:
Step-by-step explanation:
By collecting the like terms , we have:
5q - 3q = - 8 - 4 - 2p
2q = -12 - 2p
divide each term by 2 , we have
q = -6 - p
The statement that is true about the polygons is: the opposite angles of the rectangle are supplementary, therefore, a circle can be circumscribed about the rectangle.
<h3>What is a Circumscribed Quadrilateral?</h3>
An circumscribed quadrilateral is a quadrilateral whose four side lie tangent to the circumference of a circle. The opposite angles in an inscribed quadrilateral are supplementary, that is, when added together, their sum equals 180 degrees.
From the two figures given, the opposite angles of the rectangle are supplementary, therefore, a circle can be circumscribed about the rectangle. (Option D).
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LETS prove the 2nd part of the Question
Here concept of right angles is used
We can see BA is perp to BD
and BC is perp to BE
We have to prove angle 1 = angle 3
i will denote angle by a
therefore we need to prove a1 = a3
as BA is perp to BD hence angle between them will be 90 degree
a1 + a2 = 90 degree
Similarly BC is perp to BE
a2 + a3 = 90 degree
as both equations add up gives 90 degree so will equate them
a1 + a2 = a2 + a3
which means a1 = a3
Hence Proved
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