The answer is D
FeCl3 + 3 NH4OH → Fe(OH)3 + 3 NH4Cl
<span>(8.90/95.211) =0.09347 moles</span>
The answer is <span>D.when the aim is to show electron distributions in shells. This is because there are some instances when elements don't possess a regular or normal electron configuration. There are those who have special electron configurations wherein a lower subshell isn't completely filled before occupying a higher subshell. It is best to visualize such cases using the orbital notation.</span>
The Answer to your question would be A
