Let cos(−θ)=−3/5 and tanθ>0 .
1 answer:
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Answer:
a) P(t) = 330
b)P(t) →population after t years.
t →number of years.
c) Number of deer after five years = 556
Step-by-step explanation:
a) The population increasing at an annual rate of 11%, means the population is being multiplied by 1.11 each year.
So, we can use the formula
P(t) = P
P(t) = 330
P(t) = 330
b) In this model
P(t) → population after t years
P → present population
r → annual increasing rate
c) Number of population after 5 years is,
P(5) = 330
= 556
Number of deer after 5 years = 556
Answer:
Choice A) .
Step-by-step explanation:
What are the changes that would bring to
?
- Translate
to the left by
unit, and
- Stretch
. The choices of
listed here are related to
:
- Choice A)
;
- Choice B)
;
- Choice C)
;
- Choice D)
.
The expression in the braces (for example as in
) is the independent variable.
To shift a function on a cartesian plane to the left by units, add
to its independent variable. Think about how
, which is to the left of
, will yield the same function value.
Conversely, to shift a function on a cartesian plane to the right by units, subtract
from its independent variable.
For example, is
unit to the left of
. Conversely,
is
unit to the right of
. The new function is to the left of
. Meaning that
should should add
to (rather than subtract
from) the independent variable of
. That rules out choice B) and D).
- Multiplying a function by a number that is greater than one will stretch its graph vertically.
- Multiplying a function by a number that is between zero and one will compress its graph vertically.
- Multiplying a function by a number that is between
and zero will flip its graph about the
-axis. Doing so will also compress the graph vertically.
- Multiplying a function by a number that is less than
The graph of is stretched vertically. However, similarly to the graph of this graph
, the graph of
increases as
increases. In other words, the graph of
isn't flipped about the
-axis.
should have been multiplied by a number that is greater than one. That rules out choice C) and D).
Overall, only choice A) meets the requirements.
Since the plot in the question also came with a couple of gridlines, see if the points 's that are on the graph of
fit into the expression
.