To find the value of f(3) we need to follow the below steps :
Step 1 : First plot the graph of f(x)
Step 2 : We need to find f(3) or the function value at x = 3 therefore, in the graph locate the point (3,0)
Step 3 : Draw a line parallel to Y-axis passing through the point (3,0) .
Step 4 : Now there exists two cases :
If the drawn line do not intersect the graph of f(x), then no value of f(3) exists for the given function of x
If the drawn line intersects the graph, then the intersection point is marked and a line parallel to x - axis is drawn passing through that marked or intersection point. And the line where it intersects the y - axis is our required value of f(3).
If this is wrong than I guess I wasn't smart enough :)
Answer:
so the vertex is (-4, 0) and the axis of symmetry is x=-4
Step-by-step explanation:
f(x) ≥ -(x+4)^2
f(x) ≥ -(x- -4)^2
this is in the form
f(x)> a(x-h)^2 +k
where (h,k) is the vertex and h is the axis of symmetry
so the vertex is (-4, 0) and the axis of symmetry is x=-4
Answer x/3 -(-2)= 16
X/3+ 2=16
X/3=16-2
X/3=14
X= 14x3=42
Step-by-step explanation:
To solve the question, the both equations should have a positive value and a negative value with same number. Then one variable can be eliminated.
To eliminate X term first, we should multiply the first equation by 2 and second one by 3.
Then,
6X - 12Y = -30
-6X + 15Y = 70
Or
To eliminate Y term first, we should multiply the first equation by 5 and second one by 6.
Then,
15X - 30Y = -75
-12X + 30Y = 84
According to the choices given 'A' is the correct answer.
