Coastal areas experience two low tides and two high tides every lunar day, or 24 hours and 50 minutes. The two tidal bulges caused by inertia and gravity will rotate around the Earth as the moons position changes. These bulges represent high tides while the flat sides indicate low tides.
Over the course of 1 day, the position of the moon does not change very much compared to the rotation of the earth. As the earth rotates below the moon, one point on the earth will go through all levels of tide as the day passes by. Strongly attracted, middling, weakly attracted, and then middleagain. From our perspective it looks like "high, low, high, low." Or equivalently you can think about how the points below the moon and opposite the moon will be high tide, and as the earth rotates, those areas will change.
Answer:
Police powers are the fundamental ability of a government to enact laws to coerce its citizenry for the public good, although the term eludes an exact definition. The term does not directly relate to the common connotation of police as officers charged with maintaining public order, but rather to broad governmental regulatory power. Berman v. Parker, a 1954 U.S. Supreme Court case, stated that “public safety, public health, morality, peace and quiet, law and order. . . are some of the more conspicuous examples of the traditional application of the police power”; while recognizing that “an attempt to define police powers reach or trace its outer limits is fruitless.”
Answer: m= 35.6 kg
Explanation:
For finding the mass of the stone we have the formula
v=
Here, Tension= m*g = m*9.81
and linear mass density=
Linear mass density=
Linear mass density= 0.0127 kg/m
Velocity=
Velocity= 2 *
Velocity= 165.8 m/s
So putting all these values in equation we get
v=
165.8=
Solving we get
m= 35.58 kg
or m= 35.6 kg
Answer:
4.98 m
Explanation:
Given that
Width of the mirror, d = 0.6 m
Organist distance to the mirror, s = 0.78 m
Distance between the singer and the organist, S = 5.7 + 0.78 = 6.48 m
Width of north wall, D?
Using the simple relationship
D/S = d/s, on rearranging
D = dS /s
D = (0.6 * 6.48) / 0.78
D = 3.888 / 0.78
D = 4.98 m
Therefore, we can conclude that the Width of north wall is 4.98 m