C , i dont know if it’s right but it’s the only table with the same number on the bottom . and same number in general
Answer: False.
Step-by-step explanation:
There does not exist a "quarter circle" as a circle with a radius of 4 units, the only notable circle that does exist is the unit circle, that is the circle where the radius is equal to 1, represented by the equatin x^2 + y^2 = 1
The term "quarter circle" actually does refer to a fourth part of a circle, not to a circle of radius 4.
So the statement is false
Answer:
and
The ordered pair solutions are , , , and .
Step-by-step explanation:
I'm assuming the system is :
Therefore, and
The ordered pair solutions are , , , and .
Answer + Step-by-step explanation:
the inequality by finding the boundary line, then shading the appropriate area.
y > − 5/2x − 5
(anything in shaded region)
Answer:
-1
Step-by-step explanation:
mn = -3 because 3 × -1 = -3
p^2 = 4 because 2^2 = 4
Then 4 + -3 = -1