Can you find 10.5% of 600 if you divide 200

Tom wants to place a photograph that is 8.5 inches wide on his science fair poster. His poster board is 21.25 inches wide. How f

SOVA2 [1]

Answer:

6 3/8 inches (6.375 inches)

Step-by-step explanation:

For simplicity we'll assume that both the photo and the poster board are square. To determine the width of the border, subtract 8.5 inches from the poster board width 21.25 inches, obtaining 12.75 inches, and then divide that 12.75 inches by 2: 6.375 inches (6 3/8 inches).

Set the photo 6 3/8 inches from each edge of the poster board.

6 0

2 years ago

A blind taste test will be conducted with 9 volunteers to determine whether people can taste a difference between bottled water

Aloiza [94]

Answer:

The answer is $\frac{1}{256}$

Step-by-step explanation:

If we assume that people cannot taste a difference between bottled water, then the probability of identifying tap water is 0.5

Thus, P(identify tap water)=0.5

The probability that at least 8 of the 9 people identify the tap water correctly is the sum of the probabilities

8 of 9 people identified correctly or
9 of 9 people identified correctly

Since P(identify tap water)=0.5 each probabilities are the same and equal to

$0.5^9$ = $\frac{1}{512}$

So we have $2*\frac{1}{512}$ = $\frac{1}{256}$

6 0

2 years ago

"A cable TV company wants to estimate the percentage of cable boxes in use during an evening hour. An approximation is 20 percen

Marizza181 [45]

Answer:

The company should take a sample of 148 boxes.

Step-by-step explanation:

Hello!

The cable TV company whats to know what sample size to take to estimate the proportion/percentage of cable boxes in use during an evening hour.

They estimated a "pilot" proportion of p'=0.20

And using a 90% confidence level the CI should have a margin of error of 2% (0.02).

The CI for the population proportion is made using an approximation of the standard normal distribution, and its structure is "point estimation" ± "margin of error"

[p' ± $Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }$ ]

Where

p' is the sample proportion/point estimator of the population proportion

$Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }$ is the margin of error (d) of the confidence interval.

$Z_{1-\alpha /2} = Z_{1-0.05} = Z_{0.95}= 1.648$

So

$d= Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }$

$d *Z_{1-\alpha /2}= \sqrt{\frac{p'(1-p')}{n} }$

$(d*Z_{1-\alpha /2})^2= \frac{p'(1-p')}{n}$

$n*(d*Z_{1-\alpha /2})^2= p'(1-p')$

$n= \frac{p'(1-p')}{(d*Z_{1-\alpha /2})^2}$

$n= \frac{0.2(1-0.2)}{(0.02*1.648)^2}$

n= 147.28 ≅ 148 boxes.

I hope it helps!

3 0

3 years ago

Find the area use 3.14 for pi

Aleonysh [2.5K]

Answer:

15.14 cm^2

Step-by-step explanation:

Area of rectangle = 4cm x 3 cm = 12cm^2

Radius of the circle = 2 cm

Area of 1/4 of a circle = (pi x r^2) / 4

= (3.14 x 4) / 4 = 3.14 cm^2

3.14 cm^2 + 12cm^2 = 15.14 cm^2

5 0

2 years ago

Can someone please help i am very stuck :

Oliga [24]

The answer is
the first one is x= 18.98
a^2+b^2=c^2
8 cm^2+17 cm^2= x^2
64+289=x^2
√x^2= √353
x=18.89
the second one is x= 18.7
a^2+b^2=c^2
7 m^2+ x^2= 20 m^2
49 m+x^2=400 m
-49 -49
√x^2=√352
x= 18.7
Hope this helps!

5 0

2 years ago