Answer:
A. The applied force should be the same size as the friction force
Explanation:
Whenever we apply a force to an object it moves if the force applied to that object is unbalanced and there is no force or a lesser force to counter it. According to Newton's Second Law of motion, when an unbalanced force is applied to an object it produces an acceleration in the object in its own direction. So, the two forces acting on this box are the frictional force and the applied force in horizontal direction. In order to move the box at constant speed, the applied force must first, overcome the frictional force, so the object can start its motion. Since, the motion has constant velocity, it means no acceleration. So, the force must be balanced in order to avoid acceleration as a consequence of Newton's Second Law of motion. Therefore, the correction in this case will be:
<u>A. The applied force should be the same size as the friction force</u>
1000000
Explanation
No equation for the following question was given
Answer:
268.22m/s
Explanation:
Given;
10mile/min to m/s
We need to convert between the two units;
Using the dimensions;
1 mile = 1609.34m
60s = 1min
Now;
10 x x x
= 268.22m/s
The bearing shows the angle from north to the line (c), you want to see the angle inside the triangle so that will be 90-[bearing].
<span>a=42 (42 mph wind blowing north) </span>
<span>A= 90-74.9 </span>
<span>A= 15.1 degrees </span>
<span>Ground speed is the speed the plane is going including the wind. </span>
<span>ground speed = c </span>
<span>Airspeed = b </span>
<span>You have the angle, and you have the "Opposite" and want to find the "Hypotenuse". </span>
<span>SOH CAH TOA </span>
<span>Sin x = Opp/Hypot </span>
<span>Sin(15.1) = 42/c </span>
<span>c = 42/Sin(15.1) </span>
<span>c = 161.53 </span>
<span>Ground speed of the plane is 161.53 mph </span>
<span>Airspeed = b </span>
<span>Tan x = Opp/Adj </span>
<span>Tan (15.1) = 42/b </span>
<span>b = 42/Tan(15.1) </span>
<span>b = 161.53 </span>
<span>Airspeed = 161.53 mph </span>
<span>(so the answer is ground speed of 161.53mph)</span>
Answer:
thanks for the points
Explanation:
you passed the exam i see