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2 years ago

15

Divide using long division.

" alt="(x^{2} -5)" align="absmiddle" class="latex-formula"> ÷ $(x-5)$

1 answer:

Morgarella [4.7K]2 years ago

4 0

Answer:

The quotient = x + 5 and the remainder = 20

Step-by-step explanation:

$\frac{x^{2}+0-5 }{x-5}=x+\frac{5x-5}{x-5}$

$\frac{5x-5}{x-5}=5+\frac{20}{x-5}$

The quotient = x + 5 and the remainder = 20

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2 years ago

Solve y=f(x) for x. Then find the input when the output is -3.

DochEvi [55]

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Please check the explanation

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Given the function

$f\left(x\right)\:=\:\left(x-5\right)^3-1$

Given that the output = -3

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now substituting the value y=-3 and solve for x to determine the input 'x'

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switch sides

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Add 1 to both sides

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$\mathrm{For\:}g^3\left(x\right)=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt[3]{f\left(a\right)},\:\sqrt[3]{f\left(a\right)}\frac{-1-\sqrt{3}i}{2},\:\sqrt[3]{f\left(a\right)}\frac{-1+\sqrt{3}i}{2}$

Thus, the input values are:

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$x=-\sqrt[3]{2}+5$

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2 years ago

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