The percent increase in enrollment is 6 %
The operation used in first step is finding the difference between final value and initial value
<h3><u>Solution:</u></h3>
Given that This year, 1,272 students enrolled in night courses a a local college
Last year only 1,200 students enrolled.
To find: percent increase in the enrollment
The percent increase between two values is the difference between a final value and an initial value, expressed as a percentage of the initial value.
<em><u>The percent increase is given as:</u></em>
Here initial value (last year) = 1200 and final value(this year) = 1272
Substituting the values in above formula,
Thus percent increase is 6 %
Answer:
m = 36
Step-by-step explanation:
1/3 m+3- 5/6 m=-15
2m+18-5m=-90
-3m+18=-90
-3m=-90-18
-3m=-108
m=36
Step-by-step explanation:
if 'c' is meant to be another 'x' the answer is
(3, 1)
x = 3,y = 1
Answer:
C. c^2=a^2+b^2-2abcos(90°)
Step-by-step explanation:
This is the law of cosine.
Answer:
mean
Step-by-step explanation: