Question

the molar mass of l2 is 253.80g/mol and the molar mass of nl3 is the 394.71g/mol. how many moles of l2 will form 38.58 g of ni3

Answer 1

The  moles   of I2  that will   form  38.58g  of Ni3  is  0.147 moles

   calculation
write the  equation  for  reaction  for  formation of   Ni3 from I2  and N2

that is   3I2 +  N2  = 2NI3
 
find the moles  of  Ni3  formed   =  mass/molar mass

=   38.58g/ 394.71  g/mol  = 0.098  moles

by use  of  mole ratio  between  I2  to NI3  which is  3 :2 the  moles of  I2

=  0.098  x3/2 =  0.147  moles