Ask question

Ask question

All categories

2 years ago

5

When you flip a biased coin the probability of getting a tail is 0.6. How many times would you expect to get tails if you flip t

he coin 320 times?

1 answer:

laiz [17]2 years ago

4 0

Answer: I believe it’s 192 times

Step-by-step explanation:

You multiply 0.6 by 320, giving you 192

You might be interested in

Andre is setting up rectangle tables for a party. He can fit 6 chairs around a single table. Andre lined up 10 tables end to end

IRINA_888 [86]

If there is one table (t=1) then 6 chairs (c=6) can be placed around the table, 2 along the length on each side and 1 at each end.
When t=2, and the tables are end to end (joined at their width) c=10, that is, 4 chairs on each side of the double table and 1 at each end. Each time a table is added c increases by 4 so we can write c=4t+2 the constant 2 being the single chair at each end. If the tables are separated then c=6t.

5 0

2 years ago

Angie earns $55000 per year. Each year she revives a $1700 increase in annual salary. What will Angie's annual salary be for the

brilliants [131]

If she starts with 55000 per year, and she get 1700 per year extra, after fifteen years this extra will be 1700*15, or 25500. Add this to her original salary of 55000 per year to get $80500.

5 0

2 years ago

Factor the expression.

worty [1.4K]

The is will be -<span>11b3</span><span> - 16b</span>2<span> + </span>4b<span> + </span><span>3</span>

4 0

2 years ago

In a clinical test with 2161 subjects, 1214 showed improvement from the treatment. Find the margin of error for the 95% confiden

Vlad [161]

Answer:

The margin of error for the 95% confidence interval used to estimate the population proportion is of 0.0209.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

The margin of error is of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

In a clinical test with 2161 subjects, 1214 showed improvement from the treatment.

This means that $n = 2161, \pi = \frac{1214}{2161} = 0.5618$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a p-value of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

Margin of error:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$M = 1.96\sqrt{\frac{0.5618*0.4382}{2161}}$

$M = 0.0209$

The margin of error for the 95% confidence interval used to estimate the population proportion is of 0.0209.

4 0

2 years ago

Whats is 67.24 as a mixed number

masha68 [24]

<span>67 24 out of 100 i believe</span>

6 0

2 years ago

Read 2 more answers